Which of the following cylindrical rods will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The rate of heat conduction $H$ through a cylindrical rod is given by the formula $H = \frac{KA \Delta T}{L}$,where $K$ is the thermal conductivit

Vedclass · Accepted Answer

Length $1 \ m$,radius $2 \ cm$

Vedclass · Answer

(B) The rate of heat conduction $H$ through a cylindrical rod is given by the formula $H = \frac{KA \Delta T}{L}$,where $K$ is the thermal conductivity,$A$ is the cross-sectional area,$\Delta T$ is the temperature difference,and $L$ is the length of the rod.Since $A = \pi r^2$,the rate of heat conduction is proportional to $\frac{r^2}{L}$.For option $(a)$: $\frac{r^2}{L} = \frac{1^2}{1} = 1$.For option $(b)$: $\frac{r^2}{L} = \frac{2^2}{1} = 4$.For option $(c)$: $\frac{r^2}{L} = \frac{1^2}{2} = 0.5$.For option $(d)$: $\frac{r^2}{L} = \frac{2^2}{2} = 2$.Comparing these values,the ratio $\frac{r^2}{L}$ is maximum for option $(b)$,therefore it will conduct the most heat.

Which of the following cylindrical rods will conduct the most heat when their ends are maintained at the same steady temperatures?

Similar Questions

Chromatophores take part in

Viruses are ..........

Two wooden blocks of masses $M$ and $m$ are placed on a smooth horizontal surface as shown in the figure. If a force $P$ is applied to the system as shown in the figure such that the mass $m$ remains stationary with respect to the block of mass $M$, then the magnitude of the force $P$ is

$A$ mass $m$ moves with a velocity $v$ and collides inelastically with another identical mass initially at rest. After collision,the first mass moves with velocity $\frac{v}{\sqrt{3}}$ in a direction perpendicular to its initial direction of motion. The speed of the second mass after collision is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module